Javascript program to check given number is Even or Odd

In this javascript example we will write how to a program to check a given number is even or odd. We can check number is even or odd in javascript by two ways

  • Using If Else Condition
  • Using Ternary Operator

 

Using If-Else condition to check given number even or odd

<script>
// Ask user to enter a number
const num = prompt("Enter any number: ");
 
//check for even number
if(num % 2 == 0) {
    console.log("Given number is an even number.");
}
 
// check for odd number
else {
    console.log("Given number is an odd number.");
}
</script>

In the above example prompt the user to enter a number

Then converting it to integer

Now to check the number even we are divide the number with 2 and if the remainder '0' then number is Even otherwise 'odd'

Input:

33

output:

Given number is an odd number.

 

Using Ternary Operator

Ternary JavaScript operator which will takes three operands
rather than the one or two that most operators use. It use shorten a simple if else block in JavaScript programs.

Let's check example

<script>
// Ask user to enter a number
const num = prompt("Enter any number: ");
 
// apply ternary operator
const output = (num % 2  == 0) ? "even" : "odd";
 
// display result on console
console.log(`This is an ${output} number.`);
</script>

Input:

22

 

Output:

This is an even number.

 

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